SLC 2071 Solved

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SLC Question Paper 2071 Computer Science Solved Answers                                   

                                                              Subas Paudel

  1. Answer the following questions:

    a. Give two-two difference between peer-to-peer and client/server network architecture.

Ans:These are the differences between peer-to peer and client/server network architecture:

Peer-to peer Client/server
1.The type of network architecture in which

all the connected computers acts as both client and server is known as Peer-to-Peer network architecture.

1.The type of network architecture in which

all other computers in a network known as clients are handled or controlled by a single computer known as server is known as Client/Server.

2.It doesn’t have centralized server. 2.It contains  a separate centralized server.
3.It is expensive to setup and less secure. 3.It is cheaper to setup and more secure.

b. What is the function of file transfer protocol (FTP)?

Ans:The functions of File Transfer Protocol(FTP) are:

i.It enables the downloading and uploading of files into the internet.

ii.It manages the interaction between the computers on internet.

c. What is cyber crime? Give any two examples.

Ans:The crimes done through the misuse of computers , network and internet is known as cyber crime.

The two examples of cyber crime are:

i.Hacking

ii.Phishing

d. Write any four preventive measures for computer hardware security.

Ans:Any four Preventive measures for solving Hardware security problems are:

i.Insurance

ii.Regular maintenance

iii.Protection from dusts.

iv.Use of Power protection device

e. Write any two medium for transmission of computer virus.

Ans:Any two mediums for transmission of computer virus are:

i.Downloading of malicious files through internet and use of corrupted files.

ii.Sharing infected files through portable storage devices like pen drives.

 

 

2. a.Convert as indicated:

 

i.(108)10 into binary

 

Ans:

2 108 Remainder
2 54 0
2 27 0
2 13 1
2 6 1
2 3 0
  1 1

 

(108)10=(1101100)2

ii. (765)8into decimal

Ans:

(765)8=7*82+6*81+5*80

=448+48+5

=(501)10

 

∴(765)8=(501)10

b.Perform the following binary calculations:

i. 111*11

Ans

111

*11

111

+1110

10101

∴111*11=10101

 

ii. Divide 1101 by 11

Ans:                                                     

                                                                      100       

                                      11 )        1101      (100

                                                   -11         

00

-0

01

∴Quotient=100

∴Remainder=01

 

 

  1. Match the following:

i. E-commerce                     Power protection device

ii. Volt guard                         Online shopping

iii. Satellite link                      WAN

ivSound card                        Optical fiber

Multimedia

Ans:

E-commerce    –       Online shopping

Volt guard       –  Power protection device

Satellite link     –       WAN

Sound card      –      Multimedia

4. Choose the best answer:

a. Which of the following is remote login service?

Video conferencing          ii. FTP              iii. Telnet         iv. TCP/IP

Ans: Telnet

b. Process of arranging the scattered parts of file into a contiguous manner is _______.

i. debugging           ii. Backup        iii.Defragmentation      iv. Scandisk

Ans: Defragmentation

c. Which of the following is an audio input device?

Printer     ii. Microphone             iii. Head phone                        iv. Speaker

Ans: Microphone

d. Virus is a type of ___________.

i. System program  ii.Package program    iii.Destructive program   iv. Web program

Ans: destructive program

5. Technical terms:

. a. The data carrying capacity of communication channel.

Ans: Bandwidth

b. The moral principles that control cybercrime.

Ans: Computer ethics

c. Buying and selling product and services online.

Ans: E-commerce

d. An integration of text, audio, graphics and video.

Ans: Multimedia

Write down the full forms:

LAN : Local Area Network

VOIP : Voice Over Internet Protocol

Gbps : Giga bits per second

DVD : Digital Versatile Disk

 

6. Answer the following question:

a. Write any two advantages of computerized database.

AnsThe two advantages of computerized database are:

i.Larged volume of data can be stored in managed and systematic way.

ii.Retrieving of data is also easy due to data sorting and indexing.

b. Name any four objects of MS-Access database.

AnsThe four object of MS-Access are:

  1. Table
  2. Form
  3. Query
  4. Report

c. What is data sorting?

AnsThe method of arranging and grouping the data in ascending or in descending order in a database is known as data sorting.

7. State whether the following are true or false:

  1. Graphics can also be stored in MS-Access database.  True
  2. Maximum field size of memo field is 256 characters. False
  3. A form is an object of MS-Access used for entering data. True
  4. An action query makes changes in a table. True

8. Match the following:

Indexing data                     Final output

Report                                 View data

Yes/No                               Searching fast

Select query                       Picture

Data type

Ans:

  1. Indexing data   –      Searching fast
  2. Report               –       Final output
  3. Yes/No              –      Data type
  4. Select query     –       View data

 

9. Answer the following:

a. Mention the types of procedures used in QBasic.

AnsThe types of procedure used in QBasic are:

  1. Sub procedure
  2. Function procedure

b. Write two characteristics of C language.

AnsThe two characteristics of C language are:

i.It can be used for making large and powerful programmes.

ii.It’s easy for programming since it is a High Level Programming Language.

c. Write down the function of:

SHARED

AnsThe function of SHARED is to declare a variable globally.

  1. CALL

AnsThe function of CALL statement is to call sub procedure for performing specific task.

9. Re-write the following correcting the bugs:

DECLARE SUB CUBE(N)

CLS

FOR I = 1 TO 5

READ

CALL CUBE(No)

NEXT X

DATA 3, 5, 2, 6, 4

END

SUB CUBE( )

DISPLAY N^3

END SUB

Ans:

DECLARE SUB CUBE(N)

CLS

FOR I = 1 TO 5

READ No

CALL CUBE(No)

NEXT I

DATA 3, 5, 2, 6, 4

END

SUB CUBE(N)

PRINT N^3

END SUB

 

10. Write down the output:

DECLARE FUNCTION AVGE(A,B,C)

X=10

Y=5

Z=15

AV= AVGE(X,Y,Z)

RPINT “Average of three numbers”; AV

END

FUNCTION AVGE(A, B, C)

S=A+B+C

AVGE = S/3

END FUNCTION

Ans:

Average of three numbers 10

 

The output of the above programme is:

 

 

11. Study the following program and answer the following:

DECLARE SUB Stde(N$U)

FOR Loop = 1 TO 5

READ NM$(Loop)

NEXT Loop

DATA RAMA, PRATIMA, PRASANT

DATA NISHA, RUDHRA

CALL Stde(NM$U)

END

SUB Stde(N$U)

PRINT “Name starting from P”

FOR J = 1 TO 5

C$=MID$(N$,(J),1,1)

IF C$=”P” THEN

PRINT N$(J)

END IF

NEXT J

END SUB

a. List the library function used in the above program.

AnsThe library function used in the above program is MID$.

b.List the conditional statement used in the above program.

AnsThe conditional statement used in the above program is:

IF …. THEN

12. Write a program using FUNCTION….END FUNCTION to input a string and count the total number of consonants.

AnsDECLARE FUNCTION COUNT(W$)

CLS

INPUT “Enter a Word”; W$

PRINT “The total numberr of consonant is”; COUNT(W$)

END

FUNCTION COUNT (W$)

C = 0

FOR I = 1 TO LEN(W$)

B$ = MID$(W$, I, 1)

C$ = UCASE$(B$)

IF C$ <> “A” AND C$ <> “E” AND C$ <> “I” AND C$ <> “O” AND C$ <> “U” THEN C = C + 1

NEXT I

COUNT = C

END FUNCTION

13 Write a program using SUB……END SUB to find the area of circle.

AnsDECLARE SUB AREA(R)

CLS

INPUT “Enter radius”; R

CONST PI=3.14

CALL AREA(R)

END

SUB AREA(A)

A=PI*R^2

PRINT “The area of circle=”; A

END SUB

14. A data file “Salary.Dat” contains the information of employee regarding their name, post and salary. Write a program to display all the information of employee whose salary is greater than 15000 and less than 40000.

AnsOPEN “Salary.Dat” FOR INPUT AS #1

CLS

WHILE NOT EOF(1)

INPUT #1, N$, P$, S

IF S>15000 AND S<40000 THEN PRINT N$, P$, S

WEND

CLOSE #1

END

 

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